ZIMSEC O Level Combined Science Notes: Hydraulic Jack
- Has a large ram attached to the piston in a large cylinder
The diagram of the Hydraulic Jack. Image credit slideplayer.com
- A piston in a small cylinder is worked by a handle
- Pressure on this cylinder when the handle is pushed down
- is passed on through the liquid to the ram of the larger surface area
- The ram thus exerts a larger upwards force
- In order to increase the distance to which it can raise the load
- The small cylinder is fitted with vlavles
- These valves allow exra liquid to flow through when the piston is pushed down
Calculations
- Work done by the hydraulic machine can be calculated:
- For example if the area of the piston 1 is 100cm2 and
- That of piston 2 is 10cm2
- If a force of 100N on piston 2 produces pressure of:
- \dfrac{100}{10}=10N/cm^2
- This pressure is passed on to piston 1 where it acts over the entire 100cm2
- Given that:
- \text{Pressure}=\dfrac{Force}{Area}
- \text{Force}=\text{Pressure x Area}
- 10N/10cm2 x 100cm2
- 1 000N
- A 10N force can thus lift a 1 000N loadk
- Also a little movement can be translated into a larger movement of load using hydraulics
To access more topics go to the Combined Science Notes page