ZIMSEC O Level Combined Science Notes: Electric Power equations and calculations
- Power calculations that you are going to be presented with in the exam are varied
- They all depend on your knowing:
- The equation to calculate whatever variable that you are required to calculate
- Your ability to substitute and change the subject of the formula to suit your needs
- Below are some of the calculations that you might encounter during your examinations
Question 1
What is the power of an electric light operating on a 240V and using a current of 0.5A?
Solution: P=VxI
240×0.5
120 watts
Question 2
What current is drawn by an electric heater rated 2 KW operating on a 200V supply?
Solution=P=VxI
- I=\dfrac{P}{V}
- I=\dfrac{2000}{200}
- 10 \quad Amps
- Note 2kW is equal to 2000 watts
Question 3
A 2kW, 250V electric heater is used for 5 hours.
a) Calculate how much current is drawn
b) Calculate the heat energy produced
Solution:
- a) Use the equation above:
- I=\dfrac{2000}{250}
- 8 Amps
- b) Heat Produced is found using the formula:
- Heat=volts x amps x seconds
- 250 x 8 x 18000(5 hours in seconds)
- 36000000 Joules
- 36000kJ
Question 4
An electric iron is rated at 600 watts when used on a 200 Volts mains power supply:
a) Calculate how much heat it produces in 30 minutes
b) What is the resistance of the electric iron?
Solution: Heat=V*A*t(in seconds)
600 x 200 x 1800
216000000 Joules
216000 kJ
b) First find the current being drawn by the iron:
- I=\dfrac{P}{V}
- \dfrac{600}{200}
- 2 Amps
Resistance is found using the formula:
- R=\dfrac{V}{I}
- \dfrac{200}{2}
- 100\Omega
Question 5
A light bulb draws 0.5 Amps from a 250V supply.
a) What is the power of the light bulb?
b) How much heat energy does it produce in 2 hours?
c) What is the resistance of the light bulb?
Solution:
a) Power= Volts x Amps
0.5×240
120 Watts
b) Energy produced= 120 * 7200
864000 Joules
864 kJ
c) Resistance is:
- R=\dfrac{V}{I}
- \dfrac{240}{0.5}
- 480\Omega
Question 6
An electric washing machine draws a current of 10 A. If the resistance of the motor is 10 Ohms what is the power of the motor?
Solution: P=I^{2}R
- 10^{2}*10
- 1kW
To access more topics go to the Combined Science Notes page.